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Question
Draw MO diagram of CO and calculate its bond order.
Solution
Bonding in some hetero nuclear di-atomic molecules:
Molecular orbital diagram of Carbon monoxide molecule (CO)
Electronic configuration of C atom: 1s2 2s2 2p2
Electronic configuration of O atom: 1s2 2s2 2p4
Electronic configuration of CO molecule :
σ1s2, σ1s*2, σ2s2, σ2s*2, π2py2, π2pz2 σ2px2
Bond order = `("N"_"b" - "N"_"a")/2`
`= (10 - 4)/2` = 3
The molecule has no unpaired electrons hence it is diamagnetic.
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