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Question
During discharging the change taking place at cathode in lead accumulator is:
Options
Pb(s) is oxidized to \[\ce{Pb^{2+}_{(aq.)}}\]
\[\ce{Pb^{2+}_{(aq.)}}\] is oxidized to PbO2(s)
\[\ce{Pb^{2+}_{(aq.)}}\] is reduced to Pb(s)
PbO2(s) is reduced to \[\ce{Pb^{2+}_{(aq.)}}\]
MCQ
Solution
PbO2(s) is reduced to \[\ce{Pb^{2+}_{(aq.)}}\]
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