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Question
`int (dx)/(sin^2x cos^2x) dx` equals
Options
`tan x + cot x + c`
`tan x - cot x + c`
`tan x cot x + c`
`tan x - cot x + c`
MCQ
Solution
`tan x - cot x + c`
Explanation:
`int (dx)/(sin^2 x cos^2x) dx + int (cos^2x)/(sin^2x cos^2x) dx`
= `int (sin^2x)/(sin^2 x cos^2x) dx + int (cos^2x)/(sin^2x cos^2x) dx`
= `int sec^2 x dx + int "cosec"^2x dx`
= `tan x - cot x + c`
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