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Question
| Electrolyte | KCl | KNO3 | HCl | NaOAC | NaCl |
| Λ_ (S cm mol−1) |
149.9 | 145.0 | 426.2 | 91.0 | 126.5 |
Calculate
Options
517.2
552.7
390.7
217.5
Solution
390.7
Explanation:
(Λ∞)HOAC = [(Λ°)HCl + (Λ°)NaOAC] − (Λ°)NaCl
= (426.2 + 91) − (126.5)
= 390.7
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