Question

Elimination of bromine from 2-bromobutane results in the formation of ______.

Options

• Predominantly 2-butyne

• Predominantly 1-butene

• Predominantly 2-butene

• Equimolar mixture of I and 2-butene

Answer 1

Elimination of bromine from 2-bromobutane results in the formation of Predominantly 2-butene.

Explanation:

\[\begin{array}{cc}
\ce{Br}\phantom{................................................}\\
|\phantom{.................................................}\\
\ce{CH3 - CH - CH2 - CH3 ->[Alc. KOH] CH3 - CH = CH - CH3 + HBr}\end{array}\]

The formation of 2-butene is in accordance to Saytzeff's rule (more substituted alkene is formed).