Question

Energy needed in breaking a drop of radius R into n drops each of radius r is given by ____________.

Options

• 4πT (nr² - R²)

• `4/3`π (r³n - R²)

• 8πT (R² - nr²)

• 4πT (nr² + R²)

Answer 1

Energy needed in breaking a drop of radius R into n drops each of radius r is given by 4πT (nr² - R²).

Explanation:

Increase in surface area = n x 4πr² - 4πR²

Required energy is equal to the product of surface tension and increase in surface area.

= (4πnr² - 4πR²) x T