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Question
Equal volumes of three acid solutions of pH 1, 2 and 3 are mixed in a vessel. What will be the H+ ion concentration in the mixture?
Options
3.7 × 10−2
10−6
0.111
none of these
Solution
3.7 × 10−2
Explanation:
pH = −log10 [H+]
∴ [H+] = 10−pH
Let the volume be x mL
V1M1 + V2M2 + V3M3 = VM
∴ x mL of 10−1 M + x mL of 10−2 M + x mL of 10−3 M = 3x mL of [H+]
∴ [H+] = `("x"[0.1 + 0.01 + 0.001])/(3"x")`
= `(0.1 + 0.01 + 0.001)/3`
= `0.111/3`
= 0.037
= 3.7 × 10−2
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