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Question
Eu (Z = 63) and Yb (Z = 70) show + 2 oxidation state. Explain.
Answer in Brief
Solution
63Eu has electronic configuration, [Xe] 4f75d06s2. By losing 2 electrons from 6 s orbital, it acquires stable configuration and 4 f orbital is half filled.
70Yb has electronic configuration, [Xe] 4f145d06s2 . By losing 2 electrons from 6s orbital, it acquires stable configuration and 4 f orbital is completely filled.
Hence Eu and Yb show 2 + oxidation states.
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Properties of Lanthanoids
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