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Question
Evaluate:
`int_0^1 |x| dx`
Sum
Solution
`int_0^1 |x| dx`
= `int_0^1 x dx` ...[∵ x ∈(0, 1)]
= `[x^2/2]_0^1`
= `1/2 - 0`
= `1/2`
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Fundamental Theorem of Integral Calculus
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