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Question
Evaluate : `int 1/[ x(3 + log x)] dx`
Sum
Solution
Let I = `int 1/[ x(3 + log x)] dx`
Put log x = t
∴ `1/x dx = dt`
∴ I = `int 1/[(3 + t)] dt`
= log `| (3 + t) |` + c
= log `| (3 + log x) |` + c
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Indefinite Integration - Definition of an Integral
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