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Question
Explain by drawing a figure of the electronic configuration.
Formation of sodium chloride from sodium and chlorine.
Solution
There is one electron in the outermost orbit of the sodium atom, after its release, sodium becomes a positive ion. At the same time, the chlorine atom gains one electron in its outermost orbit, making the chlorine atom have eight electrons in its outermost orbit. Due to this process, chlorine negative ion is formed. Due to the electrical attraction between the positive ion of sodium and the negative ion of chlorine, an ionic bond is formed between them, and this results in the formation of sodium chloride.
\[\ce{\underset{(2, 8, 1)}{Na} -> \underset{(2, 8)}{Na+} + e-}\];
\[\ce{\underset{(2, 8, 7)}{Cl + e-} -> \underset{(2, 8, 8)}{Cl-}}\]
\[\ce{Na+ + Cl- -> NaCl}\]