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Question
Explain the reaction of 1° and 2° alcohol with oxidising agent chromic anhydride (CrO3).
Short Note
Solution
1° alcohol on oxidation in the presence of CrO3 forms aldehyde:
\[\ce{\underset{(1° alcohol)}{R - CH2 - OH} ->[CrO3][(O)] \underset{(Aldehyde)}{R - CHO}}\]
2° alcohol on oxidation in the presence of CrO3 forms ketone:
\[\begin{array}{cc}
\ce{R - CH - R' ->[CrO3][(O)] R - C - R'}\\
|\phantom{..................}||\phantom{.}\\
\phantom{.}\ce{\underset{(2° alcohol)}{OH}\phantom{...........}\underset{(Ketone)}{O}}\phantom{..}
\end{array}\]
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