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Question
Explain with diagram the boiling point elevation in terms of vapour pressure lowering.
Solution
1. The vapour pressures of a solution and of pure solvent are plotted as a function of temperature in the given diagram.
2. At any temperature, the vapour pressure of a solution is lower than that of pure solvent. Hence, the vapour pressure-temperature curve of solution (CD) lies below that of solvent (AB).
3. The difference between the two vapour pressures increases as temperature and vapour pressure increase as predicted by the equation,
Δ P = `"P"_1^0 "x"_2`
4. The intersection of the curve CD with the line corresponding to 760 mm is the boiling point of solution. The similar intersection of the curve AB is the boiling point of pure solvent. It is clear from the diagram that the boiling point of the solution (Tb) is higher than that of pure solvent `("T"_"b"^0)`.
5. At the boiling point of a liquid, its vapour pressure is equal to 1 atm.
6. In order to reach boiling point, the solution and solvent must be heated to a temperature at which their respective vapour pressures attain 1 atm.
7. At any given temperature the vapour pressure of solution is lower than that of pure solvent. Hence, the vapour pressure of solution needs a higher temperature to reach 1 atm than that needed for vapour pressure of solvent.
8. In other words, the solution must be heated to higher temperature to cause it to boil than the pure solvent.
Vapour pressure-temperature
of pure solvent and solution
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