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Question
Express the following decimal in the form `p/q`: `125.bar3`
Solution
Let `x = 125.bar3`
`rArrx=125+0.bar3`
`rArrx=125+1/3` `(because0.bar3=1/3)`
`rArrx=(375+1)/3`
`rArrx=376/3`
Hence, `125.bar3=376/3`
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