Question

`f : {1, 2, 3) -> {4, 5}` is not a function, if it is defined by which of the following?

Options

• {(2, 4), (1, 5), (3, 5)}

• {(3, 4),(1, 4),(2, 5)}

• {(1, 4),(2, 5),(3, 4)}

• {(1, 4), (2, 5), (1, 5), (3, 5)}

Answer 1

{(1, 4), (2, 5), (1, 5), (3, 5)}

Explanation:

Have (1, 4), (1, 5) ∉ `f`

Since no two first element of ordered pairs may be same.