Advertisements
Advertisements
Question
factorise : 25(2x - y)2 - 16(x - 2y)2
Sum
Solution
25(2x - y)2 - 16(x - 2y)2
= (5 (2x - y))2 - (4 (x - 2y))2
= [5(2x - y) - 4 (x - 2y)][5(2x - y) + 4(x - 2y)]
= [10x - 5y - 4x + 8y][10x - 5y + 4x - 8y]
....[a2 - b2 = (a - b)(a + b)]
= (6x + 3y)(14x - 13y)
= 3(2x + y)(14x - 13y)
shaalaa.com
Factorisation by Difference of Two Squares
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Factorise: `4/25 - 25b^2`
Factorise: (5a - 3b)2 - 16b2
Factorise: (5a - 2b)2 - (2a - b)2
Factorise: 25(2x + y)2 - 16(x - y)2
Factorise: `(7 3/10)^2 - (2 1/10)^2`
Factorise: a2 - b2 - 2b - 1
factorise: x2 + 6x + 9 - 4y2
Factorise: (a - 3b)2 - 36 b2
Factorise: 25(a - 5b)2 - 4(a - 3b)2
Evaluate (using factors) : 3012 x 300 - 3003.
