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Factorise: 250p3 + 432q3 -

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Question

Factorise: 250p3 + 432q3

Sum

Solution

250p3 + 432q3 

= 2(125p3 + 216q3)

= 2[(5p)3 + (6q)3]

= 2(5p + 6q)(25p2 + 30pq + 36q2)

shaalaa.com
Factorisation using Identity a3 + b3 = (a + b)(a2 - ab + b2)
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