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Question
Factorise a2b − b3. Using this result, find the value of 1012 × 100 − 1003.
Sum
Solution
a2b − b3
b(a2 − b2)
b(a + b) (a − b)
Now,
1012 × 100 − 1003
= 100 (1012 − 1002)
= 100 (101 + 100) (101 − 100)
= 100 (201) (1)
= 20100
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Factorisation by Difference of Two Squares
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