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Question
Factorise : a3 - `27/a^3`
Sum
Solution
a3 - `27/a^3`
= (a)3 - `(3/a)^3`
= `( a - 3/a )[ a^2 + a xx 3/a + (3/a)^2 ]` [ ∵ a3 +b3 = ( a -b )( a2 + ab + b2 )]
= `( a - 3/a )( a^2 + 3 + 9/a^2 )`
shaalaa.com
Method of Factorisation : the Sum Or Difference of Two Cubes
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