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Question
Factorise by the grouping method: 16 (a + b)2 - 4a - 4b
Sum
Solution
16 (a + b)2 - 4a - 4b
= 16 (a + b)2 - 4 (a + b)
= (a + b) [16 (a + b) - 4]
= 4 (a + b) [4 (a + b) - 1]
= 4 (a + b) (4a + 4b - 1)
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Factorisation by Grouping
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