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Question
Factorise: `m^3 + 1/(64m^3)`
Sum
Solution
`m^3 + 1/(64m^3)`
`= m^3 + (1/(4m))^3`
`= (m + 1/(4m))[m^2 - m xx 1/(4m) + (1/(4m))^2]`
`= (m + 1/(4m))(m^2 - 1/4 + 1/(16m^2))`
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