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Question
Factorise the following by grouping the terms:
2p(a2 - 2b2) -14p + (a2 - 2b2)2 - 7(a2 - 2b2)
Sum
Solution
2p(a2 - 2b2) - 14p + (a2 - 2b2)2 - 7(a2 - 2b2)
= 2p(a2 - 2b2) + (a2 - 2b2)2 - 14p - 7(a2 - 2b2)
= [2p(a2 - 2b2) + (a2 - 2b2)2] - [14p + 7(a2 - 2b2)]
= (a2 - 2b2)(2p + a2 - 2b2) - 7(2p + a2 - 2b2)
= (2p + a2 - 2b2)(a2 - 2b2 - 7).
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Factorisation by Grouping
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