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Question
Factorise the following expression.
`"x"^2-1/"x"^2`
Solution
`"x"^2-1/"x"^2`
= `("x")^2-(1/"x")^2`
= `("x"+1/"x")("x"-1/"x")` ...[∵ a2 − b2 = (a + b) (a − b)]
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