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Syllabus

Factorise: x3 + 27y3 -

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Question

Factorise: x3 + 27y3

Sum

Solution

x3 + 27y3

= x3 + (3y)3

= (x + 3y)[x2 - x(3y) + (3y)2]

= (x + 3y)[x2 - 3xy + 9y2]

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Factorisation using Identity a3 + b3 = (a + b)(a2 - ab + b2)
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