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Question
Factorise: x3 - 8y3
Sum
Solution
x3 - 8y3 = x3 - (2y)3
∴ x3 - 8y3 = x3 - (2y)3
x3 - 8y3 = (x - 2y)(x2 + 2xy + 4y2)
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Is there an error in this question or solution?
Factorise: x3 - 8y3
x3 - 8y3 = x3 - (2y)3
∴ x3 - 8y3 = x3 - (2y)3
x3 - 8y3 = (x - 2y)(x2 + 2xy + 4y2)