Factorize `6ab - B^2 + 12ac - 2bc` - Mathematics

Factorize `6ab - b^2 + 12ac - 2bc`

Taking common b in (6ab - b² )and 2c in (12ac - 2bc)

= b (6a - b) + 2c (6a - b)

Taking (6a - b) common in both terms

= (6a - b)(b + 2c)

∴ 6ab - b² +12ac - 2bc = (6a - b)(b + 2c)

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Chapter 5: Factorisation of Algebraic Expressions - Exercise 5.1 [Page 9]

Chapter 5 Factorisation of Algebraic Expressions
Exercise 5.1 | Q 7 | Page 9

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