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Question
Figure shows a ray of light as it travels from medium A to medium B. Refractive index of the medium B relative to medium A is
Options
`sqrt3//sqrt2`
`sqrt2//sqrt3`
`1//sqrt2`
`sqrt2`
Solution
`sqrt3//sqrt2`
Explanation -
Given :
Angle of incidence i = 60°, Angle of refraction r = 45°
Using snell's law we get,
Refractive index of medium B relative to medium A,
`"n"_("BA") = ("sin i")/("sin r")`
`= ("sin" 60)/("sin" 45)`
= `(sqrt3/2)/(1/sqrt2)`
= `sqrt3/sqrt2`
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