Advertisements
Advertisements
Question
Fill in the blank by suitable conversion of unit:
1 m =______ ly
Solution
1 m =1.057 × 10-16 ly
Explanation:
Light year is the total distance travelled by light in one year.
1 ly = Speed of light × One year
= (3 × 108 m/s) × (365 × 24 × 60 × 60 s)
= 9.46 × 1015 m
`:. 1m = 1/(9.46xx10^15) = 1.057 xx 10^(-16) ly`
APPEARS IN
RELATED QUESTIONS
The volume of a cube of side 1 cm is equal to ______ m3
Explain this statement clearly:
“To call a dimensional quantity ‘large’ or ‘small’ is meaningless without specifying a standard for comparison”. In view of this, reframe the following statements wherever necessary:
- Atoms are very small objects
- A jet plane moves with great speed
- The mass of Jupiter is very large
- The air inside this room contains a large number of molecules
- A proton is much more massive than an electron
- The speed of sound is much smaller than the speed of light.
A famous relation in physics relates ‘moving mass’ m to the ‘rest mass’ m0 of a particle in terms of its speed v and the speed of light, c. (This relation first arose as a consequence of special relativity due to Albert Einstein). A boy recalls the relation almost correctly but forgets where to put the constant c. He writes:
`m = m_0/(1-v^2)^(1/2)`
Guess where to put the missing c.
Fill in the blank by suitable conversion of unit:
1 kg m2s–2= ______ g cm2 s–2
Fill in the blank by suitable conversion of unit:
3.0 m s–2= ______ km h–2
Young’s modulus of steel is 1.9 × 1011 N/m2. When expressed in CGS units of dynes/cm2, it will be equal to (1N = 105 dyne, 1m2 = 104 cm2)
Photon is quantum of radiation with energy E = h ν where ν is frequency and h is Planck’s constant. The dimensions of h are the same as that of ______.
- Linear impulse
- Angular impulse
- Linear momentum
- Angular momentum
If the unit of force is 100 N, unit of length is 10 m and unit of time is 100 s, what is the unit of mass in this system of units?
Give an example of a constant which has no unit.
Calculate the solid angle subtended by the periphery of an area of 1 cm2 at a point situated symmetrically at a distance of 5 cm from the area.