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Question
Find the 12th , 24th and nth term of the A.P. given by 9, 13, 17, 21, 25, ………
Sum
Solution
We have,
a = First term = 9 and, d = Common difference = 4
[∵ 13 – 9 = 4, 17 – 13 = 4, 21 – 7 = 4 etc.]
We know that the nth term of an A.P. with first term a and common difference d is given by an = a + (n – 1) d
Therefore,
a12 = a + (12 – 1) d = a + 11d = 9 + 11 × 4 = 53
a24 = a + (24 – 1) d = a + 23 d = 9 + 23 × 4 = 101
and, an = a + (n – 1) d = 9 + (n – 1) × 4 = 4n + 5
a12 = 53, a24 = 101 and an = 4n + 5
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