Advertisements
Advertisements
Question
Find the 37th term of the AP 6 , 7 `3/4 , 9 1/2 , 11 1/4,.............`
Solution
The given AP is 6 , 7 `3/4 , 9 1/2 , 11 1/4,.............`
First term, a = 6 and common difference, d = 7`3/4 - 6 ⇒ 31/4 -6 ⇒ (31-24)/4 = 7/4`
Now , `T _37 = a + (37-1) d = a + 36 d`
= 6 +36 `xx 7/4 = 6 +63 = 69 `
∴ 37th term = 69
APPEARS IN
RELATED QUESTIONS
The 4th term of an A.P. is three times the first and the 7th term exceeds twice the third term by 1. Find the first term and the common difference.
Show that each of the progressions given below is an AP. Find the first term, common difference and next term of each .
(iii)-1 `, (-5)/6 , (-2)/3 , (-1)/2 ............`
Find:
(ii) the 35th term of AP 20,17,14,11,..........
Reshma wanted to save at least Rs 6,500 for sending her daughter to school next year (after 12 month.) She saved Rs 450 in the first month and raised her savings by Rs 20 every next month. How much will she be able to save in next 12 months? Will she be able to send her daughter to the school next year?
What value is reflected in this question ?
If Sn denotes the sum of the first n terms of an A.P., prove that S30 = 3 (S20 − S10) ?
Write the first three terms of the APs when a and d are as given below:
a = `sqrt(2)`, d = `1/sqrt(2)`
Which term of the AP: 21, 42, 63, 84,... is 210?
How many natural numbers are there between 1 and 1000 which are divisible by 5 but not by 2?
How many terms are there in an A.P. whose first and fifth terms are – 14 and 2, respectively and the last term is 62?
Which term of the A.P. : 65, 61, 57, 53, .............. is the first negative term?
