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Find a particular solution, satisfying the condition dydx=ytanx;y=1 when x=0 -

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Question

Find a particular solution, satisfying the condition `(dy)/(dx) = y tan x ; y = 1` when `x = 0`

Options

  • `y = sec x`

  • `y = tan x`

  • `y = "cosec"  x `

  • `y = cot x`

MCQ

Solution

`y = sec x`

Explanation:

`(dy)/(dx) = y tan x` or `(dy)/(dx) = tan x dx`

Integrating we get,

`int (dy)/(dx) = int tan x dx`

`log y = - log cos x + log c`

or `log y + log cos x = log c`

or `log y cos x = c`

Putting `y = 1, x = 0` ⇒ `c = 1`

∴ `y cos x` = 1

or `y = sec x` is the solution.

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