Question

Find a Pythagorean triplet in which one member is 12.

Answer 1

m² - 1 = 12

m² = 12 + 1 = 13.

Then the value of m will not be an integer.

2m = 12

m = 6

Thus, m² - 1 = 36 - 1 = 35 and m² + 1 = 36 + 1 = 37.

Therefore, the required triplet is 12, 35, 37.