Question

Find the amount of heat required to convert 100 g of water at 1000C into steam at 100°C. Latent heat of vapourisation of water is 540 calg^-1.

Answer 1

Latent heat of vapourisation of water, L=540 cal/g
Mass of water, m=100g
Amount of heat required convert 100g of water at 100°C into steam at 100°C = m x L = 100 x 540 = 5.4 kJ