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Question
Find the area of the sector of a circle whose radius is 14 cm and angle of sector is 45º
Sum
Solution
We know that the area A of a sector of angle θ in a circle of radius r is given by
`A=\frac{\theta }{360}\times\pi r^{2}`
Here, r = 14 cm and θ = 45
`\therefore A=\{ \frac{45}{360}\times \frac{22}{7}\times(14)^{2}}`
`={ \frac{1}{8}\times \frac{22}{7}\times 14\times 14}`
= 77 cm2
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