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Question
Find and correct the errors in the statement: (y − 3)2 = y2 − 9
Solution
L.H.S = (y − 3)2 = (y)2 − 2(y)(3) + (3)2 [(a − b)2 = a2 − 2ab + b2]
= y2 − 6y + 9 ≠ R.H.S
The correct statement is (y − 3)2 = y2 − 6y + 9
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