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Question
Find the currents through the three resistors shown in the figure.
Sum
Solution
From the figure, we can see that current will flow only in loop 1 because current follows the least resistive path. All the current will pass through the wire connected in parallel to the 4 Ω resistor in loop 2.
∴ There will be no current through the 4 Ω resistor in loop 2.
For loop1, applying KVL, we get:-
\[6i + 4i - 4 + 2 = 0\]
\[ \Rightarrow 10i = 2\]
\[ \Rightarrow i = 0 . 2 A\]
∴ The current through the 4 Ω and 6 Ω resistors, i = 0.2 A
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