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Question
Find the eccentricity of an ellipse whose latus rectum is half of its minor axis
Solution
\[\text{ According to the question, the latus rectum is half its minor axis }.\]
\[i . e . \frac{2 b^2}{a} = \frac{1}{2} \times \left( 2b \right)\]
\[ \Rightarrow 2 b^2 = ab\]
\[ \Rightarrow 2b = a\]
\[\text{ Now }, e = \sqrt{1 - \frac{b^2}{4 b^2}}\]
\[ \Rightarrow e = \sqrt{1 - \frac{1}{4}}\]
\[ \Rightarrow e = \frac{\sqrt{3}}{2}\]
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