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Question
Find HCF of 28, 35, 42 by Euclid’s game
Sum
Solution
HCF of 28, 35, 42
HCF of (28, 35 – 28, 42 – 28)
28 = 2 × 2 × 7
7 = 1 × 7
14 = 2 × 7
HCF of (28, 7, 14) = 7
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Euclid’s Game
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