Question

Find the minimum energy of neutron confined to a nucleus of size of the order of 10^-14m. Given mass of neutron = 1.675×10^-27kg 

Answer 1

Given data :- L=10^-14 m  
Formula :- ${\displaystyle E_n=n^2\left(\frac{h^2}{8m{l}^2}\right)\dots \dots \dots \dots \dots \dots \dots \dots .(n=1,2,3\dots ..)}$
Solution :- ${\displaystyle E_n=n^2\left(\frac{h^2}{8m{L}^2}\right)=\frac{(6.63\times {10}^{-34})\times (6.63\times {10}^{-34})}{8\times 1.67\times {10}^{-27}\times {\left({10}^{-14}\right)}^2}}$ ........(n = 1)
${\displaystyle E_1=3.29\times {10}^{-13}J}$
Lower energy = 3.29×10^-13 J