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Question
Find out the GM for the following.
| Yield of Rice (tones) | No. of farms |
| 7.5 - 10.5 | 5 |
| 10.5 - 13.5 | 9 |
| 13.5 - 16.5 | 19 |
| 16.5 - 19.5 | 23 |
| 19.5 - 22.5 | 7 |
| 22.5 - 25.5 | 4 |
| 25.5 - 28.5 | 1 |
Solution
| Yield of Rice (tones) | Mid x | f | log x | f log x |
| 7.5 - 10.5 | 9 | 5 | 0.9542 | 4.771 |
| 10.5 - 13.5 | 12 | 9 | 1.0792 | 9.7128 |
| 13.5 - 16.5 | 15 | 19 | 1.1761 | 22.3459 |
| 16.5 - 19.5 | 18 | 23 | 1.2553 | 28.8719 |
| 19.5 - 22.5 | 21 | 7 | 1.3222 | 9.2554 |
| 22.5 - 25.5 | 24 | 4 | 1.3802 | 5.5208 |
| 25.5 - 28.5 | 27 | 1 | 1.4314 | 1.4314 |
| N = 68 | ∑ f log x = 81.9092 |
GM = Antilog `((sum "f log x")/"N")`
= Antilog `((81.9092)/68)`
= Antilog (1.2045)
= 16.02 tons
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