Advertisements
Advertisements
Question
Solution
Slope of line PQ = `("y"_2 - "y"_1)/("x"_2 - "x"_1)`
= `(13 + 3)/(7 - 11) = - 16/(-4)`
= -4
Slope of line parallel to PQ
= Slope of PQ
= -4
APPEARS IN
RELATED QUESTIONS
Find the slope of the line parallel to AB if : A = (0, −3) and B = (−2, 5)
Find the value(s) of k so that PQ will be parallel to RS. Given : P(5, −1), Q(6, 11), R(6, −4k) and S(7, k2)
Find the slope and the inclination of the line AB if : A = `(-1, 2sqrt(3))` and B = `(-2, sqrt(3))`
Find the slope of the line which is perpendicular to `x - y/2 + 3 = 0`
Fill in the blank using correct alternative.
Distance of point (–3, 4) from the origin is ______.
Determine whether the given point is collinear.
\[P\left( 1, 2 \right), Q\left( 2, \frac{8}{5} \right), R\left( 3, \frac{6}{5} \right)\]
Show that A(4, –1), B(6, 0), C(7, –2) and D(5, –3) are vertices of a square.
Find the slope of a line parallel to the given line 5x-y = 10
Find the slope of a line passing through the points (x, 9) and (12, 6) is `(-1)/3 = ("y"_2 - "y"_1)/("x"_2 - "x"_1)`
Find the Slope of the line having inclination 45°.