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Question
Find the sum of 20 terms of the A.P. 1, 4, 7, 10, ……
Sum
Solution
Let a be the first term and d be the common difference of the given A.P. Then, we have a = 1 and d = 3.
We have to find the sum of 20 terms of the given A.P.
Putting a = 1, d = 3, n = 20 in
`S_n = \frac { n }{ 2 } [2a + (n – 1) d], `
`S_20 = \frac { 20 }{ 2 } [2 × 1 + (20 – 1) × 3]`
= 10 × 59 = 590
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