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Question
Find the area of the region bounded by the curve `y = x^2 + 2, y = x, x = 0` and `x = 3`
Options
`21/2` sq.units
`36/5` sq.units
21 sq.units
None of the these
MCQ
Solution
`21/2` sq.units
Explanation:
Equation of the parabola is,
`y = x^2 + 2` or `x^2 = (y - 2)`
Its vertex is (0, 2) Axis is `y`-axis.
Boundary lines are `y = x, x = 0, x = 3`
Graphs of the curve and lines have been shown in fig area of the region PQRO
Area of the region OAQR - Area of region OAP.
= `int_0^3 (x^2 + 2)dx - int_0^3 xdx`
= `[x^3/3 + 2x]_0^3 - [x^2/2]_0^3`
= `[(27/3 + 6) - 0] - (9/2 - 0)`
= `15 - 9/2`
= `21/2` sq.unit
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