Question

Find the binding energy of a H-atom in the state n = 2

Options

• 2.1 e V

• 3.4 e V

• 4.2 e V

• 2.8 e V

Answer 1

3.4 e V

Explanation:

Binding energy (BE) of atom E_n = `(13.6("z"^2))/(("n"^2)"eV")`

Now, substituting the values

For hydrogen atom (z) = 1

n = 2

E2 = `|-13.6xx("eV")/2^2|`

= `|(1.36  "eV")/4|`

= |-3.4 eV|

Hence, the required binding energy of the hydrogen atom be 3.4 eV