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Find the Difference Between the Simple Interest and Compound Interest on 2,500 for 2 Years at 4% P.A., Compound Interest Being Reckoned Semi-annualy. - Mathematics

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Question

Find the difference between the simple interest and compound interest on 2,500 for 2 years at 4% p.a., compound interest being reckoned semi-annualy.

Sum

Solution

P = ₹ 2,500
r = 4% p.a. = `(4)/(2)` = 2% half yearly
T = 2 year = 4 half years

A = P`(1 + r/100)^n`

= ₹ 2,500 `(1 + 2/100)^4`

= ₹ 2,500 `(1 + 1/50)^4`

= ₹ 2,500 `((51)/(50))^4`

= ₹`(2,500 xx 51 xx 51 xx 51 xx 51)/(50 xx 50 xx 50 xx 50)`

= ₹ `(51 xx 51 xx 51 xx 51)/(50 xx 50)`

= ₹ `(2,601 xx 2,601)/(2,500)`

= ₹`(67,65,201)/(2,500)`

= ₹ 2,706·08
C.I. = A - P

= ₹ (2,706·08 - ₹ 2,500)
= ₹ 206·08
and S.I. = `"PRT"/(100) = ₹ (2,500 xx 4 xx 2)/(100)` = ₹ 200

Difference between C.I. and S.I.
= C.I. - S.I.
= ₹ 206·08 - ₹ 200
= ₹ 6·08.

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Finding CI from the Relation CI = A – P
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Chapter 1: Compound Interest - Exercise 2

APPEARS IN

ICSE Mathematics [English] Class 10
Chapter 1 Compound Interest
Exercise 2 | Q 2

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