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Question
Find the direction ratios of a line perpendicular to both the lines whose direction ratios are 3, –2, 1 and 2, 4, –2
Sum
Solution
The vectors along the given lines are:
`bara = 3hati - 2hatj + hatk` and `barb = 2hati + 4hatj - 2hatk`
The vector perpendicular to both the vectors is given by `bara xx barb`
∴ `bara xx barb = |(hati, hatj, hatk),(3, -2, 1),(2, 4, -2)|`
= `hati(4 - 4) - hatj(-6 - 2) + hatk(12 + 4)`
= `0hati + 8hatj + 16hatk`
∴ The direction ratios of required line are 0, 8, 16 i.e. 0, 1, 2
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Vector Product of Vectors (Cross)
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