Question

Find the distance of the origin from the line 7x + 24y – 50 = 0 is:

Options

• –1

• 1

• 2

• –2

Answer 1

2

Explanation:

Given, equation of line is 7x + 24y – 50 = 0

Let P be the distance of origin from the line 7x + 24y – 50 = 0.

Compare with the general form of the equation of line

ax + by + c = 0, we have

a = 7, b = 24 and c = – 50

By distance formula, we have

P = `|c/(a^2 + b^2)|`

= `|(-50)/sqrt(49 + 576)|`

= `|(-50)/sqrt(625)|`

= `|(-50)/25|`

= | – 2 |

= 2 units