Advertisements
Advertisements
Question
Find the fourth proportional to:
x3 - y2, x4 + x2y2 + y4, x - y.
Solution
Let A be the fourth proportional then
x3 - y2 : x4 + x2y2 + y4 = x - y : A
⇒ `(x^3 - y^3)/(x^4 + x^2y^2 + y^4) = (x - y)/"A"`
⇒ A(x3 - y3) = (x - y)(x4 + x2y2 + y4)
⇒ A = `((x - y)(x^4 + x^2y^2 + y^4))/(x^3 - y^3)`
⇒ A = `((x - y)(x^2 + y^2 + xy)(x^2 + y^2 - xy))/((x - y)(x^2 + xy + y^2)`
⇒ A = x2 + y2 - xy.
APPEARS IN
RELATED QUESTIONS
If a, b and c are in continued proportion, prove that `(a^2 + ab + b^2)/(b^2 + bc + c^2) = a/c`
Using the properties of proportion, solve for x, given.
`(x^4 + 1)/(2x^2) = (17)/(8)`.
If b is the mean proportional between a and c, prove that `(a^2 - b^2 + c^2)/(a^-2 -b^-2 + c^-2)` = b4.
If a, 12, 16 and b are in continued proportion find a and b.
What number must be added to each of the numbers 5, 11, 19 and 37 so that they are in proportion?
In proportion, the 1st, 2nd, and 4th terms are 51, 68, and 108 respectively. Find the 3rd term.
If b is the mean proportional between a and c, prove that a, c, a² + b², and b² + c² are proportional.
If a, b, c, d, e are in continued proportion, prove that: a : e = a4 : b4.
Find two numbers whose mean proportional is 16 and the third proportional is 128.
Determine if the following are in proportion.
24, 28, 36, 48