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Find the interest and the amount on:₹ 4,000 in 113 years at 2 paise per rupee per month. - Mathematics

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Question

Find the interest and the amount on:
₹ 4,000 in `1 1/3` years at 2 paise per rupee per month.

Sum

Solution

Here P = Rs. 4,000, Time (T) = `1 1/3`years

= 1 years + `12/3` months = 16 months

Rate (R) = 2 paise per rupee per month = 2% per month

∴ Interest (I) `=("P"xx"T"xx"R")/100=(4,000xx2xx16)/100`

= 40 × 32

= Rs. 1280

∴ Amount (A) = P + I

= Rs. 4000 + Rs. 1280

= Rs. 5280

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Chapter 9: Interest - Exercise 9 (A) [Page 106]

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Selina Concise Mathematics [English] Class 8 ICSE
Chapter 9 Interest
Exercise 9 (A) | Q 1.4 | Page 106
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