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Question
Find the length of a second's pendulum at a place where g = 10 m s-2 (Take π = 3.14)
Solution
Given, g = 10 m/s2 and time period (T) = 2 s
Let 'l' be the length of the seconds' pendulum.
We know that `"T" = 2pisqrt(l/"g")`
⇒ `2 = 2pisqrt(l/10)`
⇒ `l/10 =1/pi^2`
⇒ `l = 10/(3.14)^2`
⇒ l = 1.0142 m
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